n^2+2n-14.9769=0

Solution for n^2+2n-14.9769=0 equation:

n^2+2n-14.9769=0

a = 1; b = 2; c = -14.9769;
Δ = b2-4ac
Δ = 22-4·1·(-14.9769)
Δ = 63.9076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{63.9076}}{2*1}=\frac{-2-\sqrt{63.9076}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{63.9076}}{2*1}=\frac{-2+\sqrt{63.9076}}{2}
$